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    Mechanical / fracture

    Fracture mechanics assessment

    A cracked component does not fail when the stress reaches yield — it fails when the stress intensity at the crack tip reaches the material toughness. That is a different question from strength, and it is the one that decides whether a pipeline, a bridge or a pressure vessel can stay in service with a known defect.

    VerdictAcceptableKr max0.942J5.4 kJ/m²
    Stress intensity
    35.45 MPa√m
    59.1% of the 60 MPa√m toughness
    Assessment point
    (0.56, 0.59)
    Lr max 1.16
    Utilisation
    62.7%
    inside the assessment line
    Critical crack
    28.6 mm
    allowable 14.3 mm at a factor of two
    Assessment working
    Two ratios, one curve, one decision.
    63%
    Assessment working
    QuantityValueNote
    Applied stress200 MParemote, away from the crack
    Crack size10.00 mmhalf-length
    Geometry factor Y1.000infinite plate, 2a
    Stress intensity K_I35.45 MPa√mY σ √(πa)
    Fracture toughness60 MPa√mK_IC or K_mat
    Toughness ratio Kr0.591K_I / K_mat
    Reference stress200 MPataken as the applied stress
    Load ratio Lr0.563σ_ref / σ_Y
    Lr cut-off1.162(σ_Y + σ_U) / 2σ_Y
    Assessment curve Kr_max0.942BS 7910 Option 1
    Utilisation62.7%below 100% is acceptable
    Critical crack28.65 mmat this stress
    Allowable crack14.32 mmhalf the critical, the usual inspection target
    J-integral5.45 kJ/m²elastic estimate
    CTOD0.0153 mmJ / σ_Y

    The two failure modes are separate: Kr measures toughness, Lr measures the approach to plastic collapse. A defect can be safe on one and unsafe on the other, which is why the assessment is a point on a diagram rather than a single number.

    Inspect the model
    Choose a quick result view, a scaled comparison, or the complete diagnostic set.
    Failure assessment diagram
    Inside the curve is acceptable. The point is the assessment; the axes are the two ways a cracked body fails.
    Failure assessment diagram0.0000.2240.4480.6720.8961.120.000.000.110.110.220.220.330.330.430.430.540.540.650.650.760.760.870.870.980.981.081.081.191.191.301.30Kr max
    Driving force against crack size
    K_I rises with the square root of the crack. Where it crosses the toughness is the critical size.
    Driving force against crack size0.00017.7635.5153.2771.0288.781mm1mm2mm2mm5mm5mm10mm10mm15mm15mm20mm20mm30mm30mm40mm40mm50mm50mmK_IToughness
    Canonical equations
    The exact relationships implemented by this engine.

    K_I = Y σ √(πa) · Y depends on geometry and loading.

    Kr = K_I / K_mat · Below 1 means the crack does not propagate.

    Lr = σ_ref / σ_Y · Capped at (σ_Y + σ_U)/2σ_Y.

    Kr_max = (1 − 0.14Lr²)(0.3 + 0.7e^{−0.65Lr⁶}) · BS 7910.

    engineering methodology

    A clear path from inputs to results.

    A cracked component does not fail when the stress reaches yield — it fails when the stress intensity at the crack tip reaches the material toughness. That is a different question from strength, and it decides whether a pipeline, a bridge or a pressure vessel can stay in service with a known defect.

    Step-by-step methodWorked exampleAssumptions explained

    How to use

    1. Enter the applied stress and the crack size.
    2. Choose the crack geometry.
    3. Set the fracture toughness and the yield and ultimate strengths.
    4. Read the assessment point and whether it sits inside the BS 7910 curve.

    The formula

    KI=Y σπa  ;  Kr=KIKmat  ;  Lr=σσYK_I = Y\,\sigma\sqrt{\pi a} \;;\; K_r = \frac{K_I}{K_{mat}} \;;\; L_r = \frac{\sigma}{\sigma_Y}

    Reference: BS 7910:2019, Guide to methods for assessing the acceptability of flaws in metallic structures, Option 1.

    Worked example

    A 10 mm centre crack under 200 MPa

    Inputs
    • 200 MPa applied stress, 10 mm half-length centre crack.
    • Toughness 60 MPa√m, yield 355 MPa, ultimate 470 MPa.
    Calculation path
    1. 1

      The geometry factor for a centre crack in an infinite plate is 1.0.

    2. 2

      The stress intensity is 200 × √(π × 0.01) = 35.45 MPa√m.

    3. 3

      That is 59.1% of the 60 MPa√m toughness, so Kr is 0.591.

    4. 4

      The load ratio is 200/355 = 0.563, and the cut-off is (355+470)/2/355 = 1.16.

    5. 5

      The Option 1 curve at Lr 0.563 gives Kr max 0.942, so the assessment uses 62.7% of the allowance and the defect is acceptable.

    6. 6

      The critical crack at this stress is 28.6 mm, so the allowable is 14.3 mm.

    Result

    K_I 35.45 · Kr 0.591 · 62.7% utilised · critical crack 28.6 mm.

    Interpreting the result

    The two axes are two different failure modes: Kr measures the approach to brittle fracture and Lr the approach to plastic collapse. A defect can be safe on one and unsafe on the other, which is why the answer is a point on a diagram rather than a single number — and why a toughness test matters more than the stress calculation.

    Assumptions & limitations

    • Option 1 of BS 7910: a generic curve and a single toughness value.
    • A centre or edge crack in an infinite plate; no finite-width correction.
    • The reference stress is taken as the applied stress.
    • Elastic J and CTOD estimates, with no ductile tearing.

    Frequently asked questions

    What is the difference between Kr and Lr?

    Kr is the ratio of the applied stress intensity to the material toughness; Lr is the ratio of the reference stress to yield. One measures toughness exhaustion, the other the approach to plastic collapse.

    Can I use this for a weld?

    Only with the weld’s own toughness and a level-2 assessment that accounts for secondary stress and the strength mismatch. Option 1 on a weld is a screening check, not a design.

    Why is the critical crack so sensitive to toughness?

    Because K_I is linear in toughness but the critical size goes with its square. Halving the toughness quarters the critical defect size.

    What is the assessment curve for?

    It defines the combination of Kr and Lr at which failure occurs. Inside the curve is acceptable; the further outside, the more certain the failure.

    Methodology last reviewed 2026-10-22. Results are informational and not financial or engineering advice — see our disclaimer.