Fracture mechanics assessment
A cracked component does not fail when the stress reaches yield — it fails when the stress intensity at the crack tip reaches the material toughness. That is a different question from strength, and it is the one that decides whether a pipeline, a bridge or a pressure vessel can stay in service with a known defect.
| Quantity | Value | Note |
|---|---|---|
| Applied stress | 200 MPa | remote, away from the crack |
| Crack size | 10.00 mm | half-length |
| Geometry factor Y | 1.000 | infinite plate, 2a |
| Stress intensity K_I | 35.45 MPa√m | Y σ √(πa) |
| Fracture toughness | 60 MPa√m | K_IC or K_mat |
| Toughness ratio Kr | 0.591 | K_I / K_mat |
| Reference stress | 200 MPa | taken as the applied stress |
| Load ratio Lr | 0.563 | σ_ref / σ_Y |
| Lr cut-off | 1.162 | (σ_Y + σ_U) / 2σ_Y |
| Assessment curve Kr_max | 0.942 | BS 7910 Option 1 |
| Utilisation | 62.7% | below 100% is acceptable |
| Critical crack | 28.65 mm | at this stress |
| Allowable crack | 14.32 mm | half the critical, the usual inspection target |
| J-integral | 5.45 kJ/m² | elastic estimate |
| CTOD | 0.0153 mm | J / σ_Y |
The two failure modes are separate: Kr measures toughness, Lr measures the approach to plastic collapse. A defect can be safe on one and unsafe on the other, which is why the assessment is a point on a diagram rather than a single number.
K_I = Y σ √(πa) · Y depends on geometry and loading.
Kr = K_I / K_mat · Below 1 means the crack does not propagate.
Lr = σ_ref / σ_Y · Capped at (σ_Y + σ_U)/2σ_Y.
Kr_max = (1 − 0.14Lr²)(0.3 + 0.7e^{−0.65Lr⁶}) · BS 7910.
A clear path from inputs to results.
A cracked component does not fail when the stress reaches yield — it fails when the stress intensity at the crack tip reaches the material toughness. That is a different question from strength, and it decides whether a pipeline, a bridge or a pressure vessel can stay in service with a known defect.
How to use
- Enter the applied stress and the crack size.
- Choose the crack geometry.
- Set the fracture toughness and the yield and ultimate strengths.
- Read the assessment point and whether it sits inside the BS 7910 curve.
The formula
Reference: BS 7910:2019, Guide to methods for assessing the acceptability of flaws in metallic structures, Option 1.
Worked example
A 10 mm centre crack under 200 MPa
- 200 MPa applied stress, 10 mm half-length centre crack.
- Toughness 60 MPa√m, yield 355 MPa, ultimate 470 MPa.
- 1
The geometry factor for a centre crack in an infinite plate is 1.0.
- 2
The stress intensity is 200 × √(π × 0.01) = 35.45 MPa√m.
- 3
That is 59.1% of the 60 MPa√m toughness, so Kr is 0.591.
- 4
The load ratio is 200/355 = 0.563, and the cut-off is (355+470)/2/355 = 1.16.
- 5
The Option 1 curve at Lr 0.563 gives Kr max 0.942, so the assessment uses 62.7% of the allowance and the defect is acceptable.
- 6
The critical crack at this stress is 28.6 mm, so the allowable is 14.3 mm.
K_I 35.45 · Kr 0.591 · 62.7% utilised · critical crack 28.6 mm.
Interpreting the result
The two axes are two different failure modes: Kr measures the approach to brittle fracture and Lr the approach to plastic collapse. A defect can be safe on one and unsafe on the other, which is why the answer is a point on a diagram rather than a single number — and why a toughness test matters more than the stress calculation.
Assumptions & limitations
- Option 1 of BS 7910: a generic curve and a single toughness value.
- A centre or edge crack in an infinite plate; no finite-width correction.
- The reference stress is taken as the applied stress.
- Elastic J and CTOD estimates, with no ductile tearing.
Frequently asked questions
What is the difference between Kr and Lr?
Kr is the ratio of the applied stress intensity to the material toughness; Lr is the ratio of the reference stress to yield. One measures toughness exhaustion, the other the approach to plastic collapse.
Can I use this for a weld?
Only with the weld’s own toughness and a level-2 assessment that accounts for secondary stress and the strength mismatch. Option 1 on a weld is a screening check, not a design.
Why is the critical crack so sensitive to toughness?
Because K_I is linear in toughness but the critical size goes with its square. Halving the toughness quarters the critical defect size.
What is the assessment curve for?
It defines the combination of Kr and Lr at which failure occurs. Inside the curve is acceptable; the further outside, the more certain the failure.
Methodology last reviewed 2026-10-22. Results are informational and not financial or engineering advice — see our disclaimer.